The final prouct"B" of the below reaction sequence is
`CH_(3) -overset(Br) overset(|)(CH) - CH_(3) overset(KOH//C_(2) H_(5) OH) to A overset((C_(6) H_(5) CO)_(2))underset(HBr) to B`

Options

A. `CH_(3)CH_(2) CH_(2)OH`
B. `CH_(3) CH= CH_(2)`
C. `CH_(3) CH_(2) CH_(2) Br`
D. `(CH_(3) CH_(2) CH_(2))_(2)O`

Answer

C

Explanation

Given,
`CH_(3) -overset(Br) overset(|) (CH) - CH _(3) overset(KOH//C_(2) H _(5)OH) to A overset((C_(6) H _(5) CO )_(2))underset(HBr) to B`
Then,
`{:(CH_(3) - overset(Br ) overset(|) (CH) - CH _(3) overset("AlcoholicKOH") underset(C_(2)H_(2) OH) to CH _(3) - CH = CH_(2)+ HBr overset((C_(6) H _(5) Co)_(2))toCH_(3) -CH_(2) - underset(Br) underset(|) CH_(2)),(" "(A) " "(B)):}`
`therefore B = CH_(3) CH _(2) CH _(2) Br`