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What is the solubility product (K(sp)) ...

What is the solubility product `(K_(sp))` of calcuim phosphate in pure water ? [S=molar solubility]

A

`108 S^5`

B

`72 S^3`

C

`6 S^5`

D

`121 S^2`

Text Solution

Verified by Experts

The correct Answer is:
A
Given ,
Calcium phosphate - `CO_2 (PO_4)_3`
Solubility product of `K_(sp)` in water = `x^x - y^y . S^(x+y)`
Here , x=2
y=3
`rArr K_(sp) = 2^2 . 3^3 . S^(2+3)`
`=4xx27xxS^5`
`=108xxS^5`
`therefore K_(sp)=108S^5`
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