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The molality (in mol kg^(-1) ) of 1 mol...

The molality (in mol `kg^(-1)` ) of 1 mole of solute in 50 g of solvent is :

A

10

B

20

C

30

D

40

Text Solution

Verified by Experts

The correct Answer is:
B
Given ,
Moles of solute , n=1
Mass of solvent , `W_A`= 50 g
Molarity of solute , `m=(nxx1000)/W_A`
`=(1xx1000)/50`
=20
`therefore` Molarity = 20 mol `kg^(-1)` .
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