A capacitance of `((10^(-3))/(2pi))` F and an inductance of `((100)/(pi))` mH and a resistance of `10 Omega` are connected in series with an AC voltage source of 220 V, 50 Hz. The phase angle of the circuit is ``60^(@)`

Options

A. `60^@`
B. `30^@`
C. `45^@`
D. `90^@`

Answer

C

Explanation

Capacitance , `C=(10^-3)/(2pi)`
Inductance,
`L=((100)/(pi))m H=(100)/(pi) xx 10^(-3)H`
`R= 10 Omega`
voltage `=220 ` volt
Frequency , `f=50 H_3`
phase angle, `phi =tan phi =(X_L- X_c)/( R)`
`X_L = Omega L =` inductive impendece `=2 pi f` L
`X_(c) =(1)/(2) pi fc`
`tan phi =((2pi xx 50 xx (100)/(pi)xx10^(-3))-((1xx 2pi )/(2pi xx 50 xx10^-3)))/(10)=(20-10)/(10)=1`
`theta =45^@`.