The following reaction occurs in acidic medium
`KMnP_(4) + 8 H^(+) 5e^(-) to K^(+) Mn^(2+) + 4H_(2) O`
what is the equivalent weight of `KMnO_(4)`?
[Molecular weight of `KMnO_(4) = 158`]

Options

A. `79.0`
B. `31.6`
C. `158.0`
D. `39.0`

Answer

B

Explanation

Reaction in acidic medium
`KMnO_(2)+8H^(+)+5e^(-)to K^(+)Mn^(+2)+4H_(2)O`
In acidic medium `KMnO_(4)` acts as an oxidising agent. `KMnO_4` from reductant gains 5 electrons `KMnO_4` equivalent weight `=(158)/(5) =31.6g`.