The molality of an aqueous dilute solution containing non-volatile solute is 0.1 m. What is the boiling temperature (in `.^(@)C`) of solution? (Boiling point elevation constant, `k_(b) = 0.52 kg mol^(-1) K` boiling temperature of water `= 100 .^(@)C`)

Options

A. `100.0052`
B. `100.052`
C. `100.0`
D. `100.52`

Answer

B

Explanation

`K_(b)=0.52 kg mol ^(-1)K`.
Water boiling point `=100^@ C` .
`m=(Delta T_b)/(K_b)`
`0.1 =(Delta T_b)/(0.52)`
`Delta T_b =0.052`.
Solution boiling point `(T_b)=100+Delta T_b`
`=100+0.052`
`100.052`.