For the reaction
`5 Br(aq) + BrO_(3)^(-)(aq) + 6H^(+)(aq) to 3 Br_(3)(aq) + 3H_(2)O(l)`
If, ` -(Delta[Br])/(Deltat) = 0.05 mol L ^(-1)mi n^(-1) , -(Delta[BrO_(3)])/(Deltat) in mol L ^(-1)mi n^(-1) is`

Options

A. `0.01`
B. `0.3`
C. `0.03`
D. `0.005`

Answer

C

Explanation

`5Br -(aq)+6H^(+)(aq)to 3Br_(2)(aq)+3H_(2)O(l)`
`r_(av)=(-Delta [R])/(Delta t)=(Delta [P])/(Delta t)`
R= reactant
p=product
From the formula.
`-(1)/(5)(Delta [Br^(-)])/(Delta t)=-(Delta [BrO_(3)^(-)])/(Delta t)=+(1)/(3) (Delta [Br_2])/(Delta t)`
`therefore (Delta [BrO_(3)^(-)])/(Delta t) =(1)/(3) (Delta [Br_2])/(Delta t)`
`rArr (Delta [Br_2])/(Delta t)=3 (Delta [BrO_(3)^(-)])/(Delta t)`
`=3xx0.01`
`=0.03`.