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If A = [(a+ib,c+id),(-c+id,a-ib)], a^(2)...

If `A = [(a+ib,c+id),(-c+id,a-ib)], a^(2)+b^(2)+c^(2)+d^(2) =1`, then find inverse of A.

A

`[{:(a+jb, -c-id),(c-id, a-ib):}]`

B

`[{:(a-ib, c+id),(-cid, a-ib):}]`

C

`[{:(a-b, -c-id),(c-id, a+ib):}]`

D

`[{:(a+ib, c + id),(c-id, a-ib):}]`

Text Solution

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The correct Answer is:
C
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