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The dimensional formula of 1/2mu(0)H^(2)...

The dimensional formula of `1/2mu_(0)H^(2) (mu_(0)` = permeability of free space and H = magnetic field intensity) is

A

`[MLT^(-1)]`

B

`[ML^(2)T^(-2)]`

C

`[ML^(-1)T^(-2)]`

D

`[ML^(2)T^(-1)]`

Text Solution

Verified by Experts

The correct Answer is:
C

Dimensional formulae are `mu_(0) = [MLT^(-2)I^(-2)] and H = [IL^(-1)]`
On substituing the above formulae in given equation = `1/2 [MLT^(-2)I^(-2)][IL^(-1)]^(2) = [ML^(-1)T^(-2)]`
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