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The displacement of a particle moving in...

The displacement of a particle moving in a straight line Is given by the expression `x = At^(3) + Bt^(2) + Ct + D`meters, where t is in seconds and A, B, C and D are constants. The ratio between the initial acceleration and initial velocity is

A

(a) `2C/(B)`

B

(b) `2B/(C)`

C

( c ) `2C`

D

(d) `C/(2B)`

Text Solution

Verified by Experts

The correct Answer is:
(b)

`x = At^(3) + Bt^(2) + Ct + D`
Velocity, `V=dx/(dt)= 3At^(2) +2Bt + C`
At t = 0,`V_(I"nitial") = C`
Acceleration,`a = d^(2)x/dt^(2)= 6At + 2B`
At t = 0, `a_("initial") = 2B` `a_("initial")/(V_("initial")) = 2B/(C)`
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