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Sum of magnitude of two forces is 25 N. ...

Sum of magnitude of two forces is 25 N. The resultant of these forces is normal to the smaller force and has a magnitude of 10 N. Then the two forces are

A

14.5 N, 10.5 N

B

16 N, 9 N

C

13 N, 12 N

D

20N, 5N

Text Solution

Verified by Experts

The correct Answer is:
A

`F_(1) + F_(2)=25`
`implies F_(1)+ F_(2)cos theta=0`
`F_(res) = sqrt(F_(1)^(2) + F_(2)^(2) + 2F_(1) F_(2) cos theta)`
`implies 100 = F_(1)^(2) + F_(2)^(2) + 2F_(1) F_(2) cos theta `
`implies F_(1)^(2) + (25-F_(1))^(2) + 2F_(1) F_(2) cos theta=100`
`F_(1)^(2) + 625 + F_(1)^(2) -50F_(1) + 2F_(1) F_(2) cos theta= -525 `
`50F_(1)=525`
`F_(1) = 10.5, F_(2) = 25 - 10.5 = 14.5`.
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