A bullet of mass 0.02 kg travelling horizontally with velocity 250 `ms^(-1)`strikes a block of wood of mass 0.23 kg which rests on a rough horizontal surface. After the impact, the block and bullet move together and come to rest after travelling a distance of 40 m. The coefficient of sliding friction of the rough surface is `(g = 9.8 ms^(2))`

Options

A. 0.75
B. 0.61
C. 0.51
D. 0.3

Answer

C

Explanation

After collision the bullet and block move combinedly and comes to rest after covering a distance of 40 m.
From Law of conservation of Linear momentum
`m_(1)u_(1)=m_(2)u_(2)= m_(1)V_(1)=m_(2)V_(2)`
`m_(1)=0.02u_(1)=250m_(2)=0.23u_(2)=0`