A ball of mass 100 g is moving with a velocity of 10 `ms^(-1)`. On being hit with bat rebounds with a velocity of 10 `ms^(-1)`. The force of the ball by the bat acts for 0.01 s, then the force exerted on the ball by the bat is

Options

A. 50 N
B. 100 N
C. 200 N
D. 400 N

Answer

C

Explanation

`V_(1) = 10 ms^(-1), v_(2) = - 10 ms^(-1), Delta t = 0.01 s,m= 100 g`
Force`=(m(v_(1)-v_(2)))/(Delta t)`
`=(0.1[10+10])/0.01 = 200 N`