The moment of inertia of a disc, of mass M and radius R, about an axis which is a tangent and parallel to its diameter is

Options

A. `(1)/(2)MR^(2)`
B. `(3)/(4)MR^(2)`
C. `(1)/(4)MR^(2)`
D. `(5)/(4)MR^(2)`

Answer

(d)

Explanation

The moment of inertia of a disc, about an axis which is a tangent and parallel to its diameter is given as,
`I=I_(0)+MR^(2)`
Where,
`I_(0)=`Moment of inertia of the circular disc`=(MR^(2))/(4)`
implies `I_(0)=(MR^(2))/(4)+MR^(2)`
`therefore I=(5)/(4)MR^(2)`