The position of a particle is given by `vecr=(hati+2hatj-hatk)`momentum `vecp=(3hati+4hatj-2hatk)`The angular momentum is perpendicular to

Options

A. x-axis
B. y-axis
C. z-axis
D. Line at equal to all the three axes

Answer

(a)

Explanation

`vecr=hati+2hatj-hatk`
`vecp=3hati+4hati-2hatk`
Angular momentum,
`vecl=vecrxxvecp`
`|(hati,hatj,hatk),(1,2,-1),(3,4,-2)|`
`=hati(-4+4)-hatj(-2+3)+hatk(4-6)`
`=-hatj-2hatj`
Therefore, the angular momentum is perpendicular x-axis.