The relation between efficiency `'eta'` of a heat engine and the co-efficient of performance `'alpha` of a refrigerator is

Options

A. `eta=1/(1-a)`
B. `eta=1/(1+a)`
C. `eta=1+a`
D. `eta = 1-a`

Answer

B

Explanation

`etaQ_(1) =Q_(1)-Q_(2)`
`implies` `alpha =Q_(2)/(etaQ_(1))`
`implies` `alpha=(1-eta)/(eta)`
`therefore` `eta=(1)/(1+alpha)`