If on heating liquid through `80^(@)C`, the mass expelled is `(1/100)^(th)`of mass still remaining , the coefficient of apparent expansion of liquid is

Options

A. `126.5xx10^(-4//@)C`
B. `0.8 xx 10 ^(-4//@) C`
C. `1.25 xx 10^(-6//@)C`
D. `1.25 xx 10^(-4//@)C`

Answer

D

Explanation

Apparent expansion of liquid,
`gamma_(a)= ("Mass of expelled liquid")/("Mass of rem. Liquid "xx Deltat)`
`gamma_(a)= m_(e)/(m_(r)xx Deltat)`
But given, `m_(e) = m_(r)/(100)`
`therefore gamma_(a)= (m_(r))/(100xxm_(r)xx80^(@)C`
`gamma_(A)= 0.125xx10^(-3) = 1.25xx10^(-4)//^(@)C`