When heat energy of 1500 J is supplied to a gas at constant pressure , `2.1 xx 10^(5) Nm^(-2)` , there was an increase in its volume equal to `2.5 xx 10^(-3) m^(3).` The increase in its internal energy in joule is

Options

A. 450
B. 525
C. 975
D. 2025

Answer

C

Explanation

From first law of thermodynamics,
`dQ=dU+dW`
(or) `dU=dQ-dW=dQ-pdv`
`= 1500-(2.1xx10^(5)xx2.5xx10^(-3))=975 J`