A liquid of mass M and specific heat s is at temperature 2t . If another liquid of same mass, specific heat 1.5 times s at a temperature of `(t)/(3)` is added to it, the resultant temperature will be

Options

A. `(4)/(3) t`
B. `t`
C. `(t)/(2)`
D. `(2t)/(3)`

Answer

B

Explanation

Resultant temperature , `t _(R) = (m_(1) s_(1) t_(1) + m_(2) s_(2) t_(2))/(m_(1) s_(1) + m_(2) s_(2))`
`implies t_(R) = ((m xx sxx2t)+ (1.5 xx m xx s xx (t)/(3)))/(m xx s + (1.5 xxmxxs))`
`implies t_(R) =( 2t + (1.5 xx(t)/(3)))/ (1 + 1.5)`
`therefore t_(R) = t `