Coefficient of real expension of mercury is `0.18 xx 10^(-3//@)C`. If the density of mercury at `0^(@)C` is `13.6 g//C C`, its density at 473 K will be

Options

A. `13.11 g C C^(-1)`
B. `13.65 g C C^(-1)`
C. `13.51 g C C(-1)`
D. `13.22 g C C^(-1)`

Answer

A

Explanation

Coefficient of real expansion ,
`gamma=(d_(0)-d_(1))/(d_(0)(Deltat))`
`implies 0.18xx10^(-3) =(13.6-d_(1))/(13.6(473-273))`
`therefore d_(1)=13.110 g c c^(-1)`