A iron ball of mass `0.2 kg ` is heated to `100^(@)C` and put into a block of ice at `0^(@)C`.25 g of ice melts , then specific heat of iron ( in cal` kg^(-10) C^(-1) )` is [ Latent heat of fusion of ice = `80 cal g^(-1)`]

Options

A. 1
B. `0.1`
C. `0.8`
D. `0.08`

Answer

B

Explanation

From principle of calorimetry
Heat absorbed = Heat released
`M_(1)L = m_(2)sDeltat`
`implies (25)(80) = (0.2)s(100) xx 10^(3)`
`therefore s = 0.1 cal Kg^(-1)C^(-1)`