Work done by `0.1` mole of gas at `27^(@)C` when it expands to double its volme at constant pressure is (assume `R = 2 cal//mol-K`)

Options

A. 600 cal
B. 42 cal
C. 60 cal
D. 546 cal

Answer

B

Explanation

Work done at constant pressure,
`W = 2.3026 nRT log10 ((v_(2))/(v_(1)))`
`W = 2.3026 xx 0.1 xx 2 xx 300 log ((2v)/(v))`
`W = 41.58 cong 42 cal`