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The diameter of objective of a telescope...

The diameter of objective of a telescope is 1 m. Its resolving limit for the light of wavelength 4538 ` overset(circ)(A)`, will be

A

`5.54 xx 10^(-7) rad`

B

`2.54 xx 10^(-4) rad`

C

`6.54 xx 10^(-7) rad`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
a

Resolving limit `d theta=(1.22lambda)/a`
`lambda = 4538 overset(circ)(A),a=1m`(Given)
`dtheta=(1.22xx4538xx10^(-10))/1`
`=5.54xx10^(-7) rad`
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