A charge of `1 mu`C is divided into parts such that their charges are in the ratio of 2: 3. These two charges are kept at a distance 1 m apart in vacuum. Then, the electric force between them (in N) is

Options

A. 0.216
B. 0.00216
C. 0.0216
D. 2.16

Answer

(b)

Explanation

`q_(1) = 2/5 mu C ` and q = `3/5 mu `C
Electrostatic force between the two charges is,
`F = 1/4 pi epsilon_(0) q_(1)q_(2)/d^(2)= 9 xx 10^(9) xx2/5 xx 10^(-6) xx 3/5 xx 10^(-6)/(1)^(2)`
= 0.00216 N