A particle of mass `1 xx 10^(-26)` kg and charge `1.6 xx 10^(-19)` C travelling with a velocity `1.28 xx 10^(6) ms^(-1)` along the positive x-axis enters a region in which a uniform electric field `vec E` and a uniform magnetic field on induction `vec B` are present. It `vec E = - 102.4 xx 10^(3) hat K NC^(-1)` and `B = 8 xx 10^(-2) hat j Wbm^(-2)`, the direction of motion of the particle is

Options

A. Along the positive x-axis
B. Along the negative x-axis
C. At `45^(0)` to the positive x-axis
D. At `135^(0)` to the positive x-axis

Answer

( a)

Explanation

The direction of motion of particle is ,
`|vec E|\|vec B| = 102.4 xx 10^(3)/8xx10^(-2) = 1.28 xx 10^(6)`
Therefore, the direction of motion of particle is along the positive x-axis.