The time in second required to produce a potential difference of 20 V across a capacitor of 1000 `mu`F when it is charged at the steady rate of 200 `mu C//s` is

Options

A. 50
B. 100
C. 150
D. 200

Answer

(b)

Explanation

Total charge ,q=cv = `(1000 xx 10^(-6) xx 20 )= 2 xx 10^(-2)`
Rate of charge = 200 `muC//s`
`:.` Time taken = `2 xx 10^(-2)/200 xx 10^(-6) = 100 s`