Two capacitors 2 `mu`F and 4 `mu`F are connected in series and a potential of 100 V is applied across the combination. Energy stored in the capacitors is

Options

A. 0.0067 J
B. 0.067 J
C. 0.0033 J
D. 0.057 J

Answer

(a)

Explanation

Equivalent capacitance , C =`C_(1)C_(2)/C_(1) + C_(2) = 2xx 4 / 2+4 = 4/3 mu`F
Energy stored,
`E = 1/2 CV^(2)`
`=1/2 xx 4/3 xx 10^(-6) xx 10^(4)`
= 0.0067 J