A parallel plate capacitor has a capacitance of 10 `mu`F without dielectric. A dielectric of dielectric constant 2 is used to fill exactly half the thickness between the plates. The capacitance in `mu`F, now is

Options

A. 10
B. 20
C. 15
D. 13.33

Answer

(d)

Explanation

Capacitance without dielectric,
`C_(a) = 10 mu`F
Capacitance with dielectric,
`C = Aepsilon_(0)/d - d/2 + d/2k `
`= 2A epsilon_(0) / s[1+ 1/k]`
`= 2C_(a)/1 + 1/k = 2 xx 10/1 + 1/2 = 13.33 mu`F