A material of 0.25 cm^(2) cross sectiona...

A material of `0.25 cm^(2)` cross sectional area is placed in a magnetic field of strength (H) `1000 Am^(-1)`. Then the magnetic flux produced is (Susceptibility of material is 313)(Permeability of free space,`mu=4pixx10^(-7)Hm^(-1)`

`8.33xx10^(-8)Weber`

`1.84xx10^(6) Weber`

`9.87xx10^(-6) Weber`

`8.33xx10^(-8)Weber`

Text Solution

Verified by Experts

The correct Answer is:

`phi=vecB.vecA=BA`
`=muHA`
`=mu_(0)(1+chi)HA`
`=4pixx10^(-7)(314)xx10^(3)xx25xx10^(-6)`
`cong9.87xx10^(-6)`Weber.

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