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Magnetic field induction at the centre of a circular coil of radius 5 cm and carrying a current 0.9 A is (in SI units) (`in_(0)=` Absolute permitivity of air in SI units: velocity of light = `3xx10^(8)ms^(-1)`)

A

`(1)/(in_(0)10^(16))`

B

`(10^(16))/(in_(0))`

C

`(in_(0))/(10^(16))`

D

`10^(16)in_(0)`

Text Solution

Verified by Experts

The correct Answer is:
A

Magnetic field induction at the centre of the circular coil
`B=(mu_(0)I)/(2r)`
`C=(1)/(sqrt(mu_(0)epsilon_(0)`
`mu_(0)=(1)/(epsilon_(0)C^(2))=(1)/(epsilon_(0)xx9xx10^(16))`
`B=(0.9)/(epsilon_(0)xx9xx10^(16)xx2xx5xx10^(-2))`
`B=(1)(epsilon_(0)10^(16))`
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