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Magnetic induction at the centre of a ci...

Magnetic induction at the centre of a circular loop of area `pim^(2)` is 0.1 T. The magnetic moment of the loop is (`pi_(0)=` permeability of air)

A

`(0.1pi)/(mu_(0))`

B

`(0.2pi)/(mu_(0))`

C

`(0.3pi)/(mu_(0))`

D

`(0.4pi)/(mu_(0))`

Text Solution

Verified by Experts

The correct Answer is:
B

Magnetic induction at the centre of circular loop
`B=(mu_(0)ni)/(2r)`
Magnetic moment of the loop, `m=niA=(2BrA)/(mu_(0))`
`implies M=(2xx0.1xxpixx(1)^(2))/(mu_(0))`
`therefore M=(0.2pi)/(mu_(0))`
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