A particular of mass 0.6 g and having charge of 25 nC is moving horizontally with a uniform velocity `1.2xx10^(4) ms^(-1)` in a uniform magnetic induction is (`g=10 ms^(-2)`)

Options

A. Zero
B. 10 T
C. 20 T
D. 200 T

Answer

C

Explanation

The particle is moving horizontally, so
Magnetic force =Gravitational force
Bqv=mg
`B=mg/qv=(0.6xx10^(-3)xx10)/(25xx10^(-9)xx1.2xx10^(4))=(6xx10^(-3))/(30xx10^(-5))=20 T.`