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A magnetic of length 10 cm and magnetic ...

A magnetic of length 10 cm and magnetic moment 1 `Am^(2)` is placed along side AB of an equilateral triangle ABC. If the length of the side AB is 10 cm. The magnetic induction at the point C is `(mu_(0)=4pixx10^(-7) Hm^(-1))`

A

`10^(-9) T`

B

`10^(-7) T`

C

`10^(-5) T`

D

`10^(-4) T`

Text Solution

Verified by Experts

The correct Answer is:
D

Magnetic induction at point C
`B=(mu_(0))/(4pi)(m)/(d^(2))`
`implies m=(M)/(2l)=(1)/(0.1)=10 AM`
`implies B=(10^(-7))((10)/(0.01))=10^(-4)T.`
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