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The couple acting on a magnet of length ...

The couple acting on a magnet of length 10 cm placed in a uniform magnetic field of intensity `40 NA^(-1)m^(-1)` such that the axis of the magnet makes `45^(@)` with the field direction is `sqrt2/10 Nm`. The pole strength of the magnet (in Wb) is

A

`5xx10^(-3)`

B

0.5

C

0.05

D

5

Text Solution

Verified by Experts

The correct Answer is:
C

Couple acting on a magnet, `tau=MB"sin"theta`
`(sqrt2)/(10)=Mxx40xx"sin"45^(@)`
`implies M=(sqrt2xxsqrt2)/(40xx10)=1/200`
`implies M=mxx2l`
`implies M=(M)/(2l)=(1)/(200xx10xx10^(-2))`
`=(1)/(2xx10)=0.05`
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