If a bar of moment mu is suspended in a ...

If a bar of moment mu is suspended in a uniform magnetic field B and it is given an angular deflection theta w.r.t. its equilibrium position, the restoring torque on magnet is

`muB"sin"theta`

`muB"cos"theta`

`muB"tan"theta`

`mu^(2)B^(2)"sin"theta"cos"theta`

Text Solution

Verified by Experts

The correct Answer is:

Restoring torque on the magnet, `tau=MB"sin"theta`
Given `M=mu`
So, `tau=muB"sin"theta`

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