A conducting rod of length L rotates with angular speed `omega` in a uniform magnetic field of induction B which is perpendicular to its motion .The induceed emf developed between the two ends of the rod is

Answer

B

Explanation

EM.f induced between the two ends of the rod is given by,
e=Blv sin 0
`implies `e=Blv [`therefore `0=`90^(@)`
`implies` e=Blxx`(Omegal)/(2)`
`therefore e=(Bomega^(2))/(2)`