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The De-Broglie wavelength of an electron...

The De-Broglie wavelength of an electron moving with a velocity of `1.5xx10^8ms//s` is equal to that of a photon The ratio of kinetic energy of the electron to that of the photon `(c=3xx10^8m//s`)

A

2

B

4

C

`1/2`

D

`1/4`

Text Solution

Verified by Experts

The correct Answer is:
d
The ratio of kinetic energy of electron to photon is given by,
`V/(2c)=(1.5xx10^8)/(2xx3xx10^8)=1/4`
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