For 6 trials of an experiment, let X be a binomial variate which satisfies the relation `9P(X = 4) = P(X = 2)`. Find the probability of success.

If in 6 trials, X is a binomial variate which follows the relation 9P(X=4)=P(X=2), then the probability of success is

A binomial random variable X ·satisfies the reiation 9P(X = 4) = P(X =2) when n= 6. Find the parameter p.

A binomial random variable X satisfies the relation 9P(X=4)=P(X=2) when n=6. Find the value of the parameters p.

In 6 trails x is binomial variate which follows 4P(X=4)=P(X=2) then the probability of success is

X is a binomial variate with parameters n=6 and p. If 4P(X=4)=P(X=2) , then p is s

For a binomial variate X , if n = 3 and 4P (X=1) = 3P (X=3) , then p (probability of success)

If for a binomial distribution with n=5, 4P(X=1)=P(X=2) , the probability of success is

If in 6 trials of an experiment the probability of a successes is 5 times the probability of a failure, then find the probability of two successes.