Given A=(0,6),B=(4,0),C=(-3,0), the orthocenter of `Delta ABC` is

" Given "A=(0,6),B=(4,0),C=(-3,0),D=(0,-2)" concylic points,the orthocenter of "Delta ABC" is "

Let A-=(-2,0),B-=(4,0),C-=(h,h) . If perimeter of triangle ABC is minimum,then

A(-3,-4), B(-5,0),C(3,0) are the veties of Delta ABC . Fin the co-ordinates of the circumcentre of Delta ABC.

" Let "A-=(-2,0),B-=(4,0),C-=(h,h)" .If perimeter of triangle "ABC" is minimum,then "

If A(0,0),B(2,4) and C(6,4) are the vertices of a Delta ABC, find theof its sides.

Let A(0,0),B(0,5)&C(3,4) be the vertices of a triangle.If H(alpha,beta) be the orthocenter of Delta ABC and H_(1)(a,b) be the orthocenter of Delta ABH , then the value of (a)/(b)=

Let A(3,4) B(5,0), C(0,5) be the vertices of a triangle ABC then orthocentre of Delta ABC is (alpha, beta) Find alpha + beta

A triangle whose mid points in between the sides (6,0),(0,8) and (6,8), the orthocenter of triangle