if `tan(theta/2)=cosectheta-sintheta` then `cos^2(theta/2)`

If tan\ theta/2=cosectheta-sintheta, then- a. sin^2\ theta/2=2sin^2\ 18^@ b. cos2theta+2costheta+1=0 c. sin\ theta/2=4sin^2\ 18^@ d. cos2theta+2costheta-1=0

If tan((theta)/(2))=(cos ec theta-sin theta) then tan^(2)((theta)/(2))=

If cos^2theta-sintheta=1/4 then sintheta=?

If sin theta=cos theta then 2tan theta+cos^(2)theta=

frac(sintheta [(1-tantheta) tan theta+sec^2 theta])((1-sintheta) tantheta(1+tan theta) (sec theta+tantheta)) =?

Prove that (cos theta-sintheta)/(cos theta+sintheta)=sec 2 theta-tan 2theta .

If sintheta + cosectheta = 2 then sin^6theta + cosec^6theta is..

If sintheta + cosectheta = 2 then sin^6theta + cosec^6theta is..

If sintheta_(1)+sintheta_(2)+sintheta_(3)=3, then cos theta_(1)+cos theta_(2)+cos theta_(3)=

tan^(2)theta-tan^(2)(90^(@)-theta)=(sin^(2)theta-cos^(2)theta)/(sin^(2)theta cos^(2)theta)