If the normal to the ellipse `(x)/(18)+(y)/(8)=1` at point `(3,2)` is `ax-by-c=0` .(where gcd(a,b,c)=1) .Then the value of `a+b+c` ?

If the normal to the ellipse " (x^(2))/(18)+(y^(2))/(8)=1 " at point (3,2)" is "ax-by-c=0" .(where "gcd(a,b,c)=1)" .Then the value of a+b+c=?

Find the normal to the ellipse (x^(2))/(18)+(y^(2))/(8)=1 at point (3,2).

If x^(2)y+y^(3)=2 then the value of (d^(2)y)/(dx^(2)) at the point (1,1) is (-(a)/(b)) where g.c.d(a, b)=1 then a+b=

If y = x + c is a normal to the ellipse x^2/9+y^2/4=1 , then c^2 is equal to

The line y=mx+c is a normal to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1, if c

A tangent is drawn to the ellipse to cut the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 and to cut the ellipse (x^(2))/(c^(2))+(y^(2))/(d^(2))=1 at the points P and Q. If the tangents are at right angles,then the value of ((a^(2))/(c^(2)))+((b^(2))/(d^(2))) is

If the line (ax)/(3)+(by)/(4)= cbe a normal to the ellipse (x^(2))/(a^(2))+(y^(2))/(a^(2))=1, show that 5c=a^(2)e^(2) where e is the eccentricity of the ellipse.