If the axes are shifted to the point `(1,-2)` without rotation, what do the following equations become? `2x^2+y^2-4x+4y=0` `y^2-4x+4y+8=0`

If the axes are shifted to the point (1,-2) without rotation,what do the following equations become? 2x^(2)+y^(2)-4x+4y=0y^(2)-4x+4y+8=0

If the origin is shifted to the point (1,-2) without the rotation of the axes, what do the following equations become? (i) 2x^2+y^2-4x+4y=0 (ii) y^2-4x+4y+8=0

If origin is shifted to point (1,-2) then find the new transformed form of the following equation. (i) 2x^(2) + y^(2) - 4x+ 4y =0 (ii) y^(2) - 4x + 4y + 8=0

When the origin is shifted to (-1,2) by the translation of axes, find the transformed equation of 2x^2+y^2-4x+4y=0

If the origin is shifted to the point (1,2) then what will be the transform equation of the following equations, it is given that the new and old axes are parallel : (i) x^(2)+y^(2)-2x-4y=0 (ii) 2x^(2)-y^(2)-4x+4y-3=0 (iii) x^(2)+xy-2y^(2)-4x+7y-5=0 (iv) 3x+y=6

If origin is shifted to the point (-1,2) then what will be the transformed equation of the curve 2x^(2)+y^(2)-3x+4y-1=0 in the new axes ?

If origin is shifted to the point (-1,2) then what will be the transformed equation of the curve 2x^(2)+y^(2)-3x+4y-1=0 in the new axes ?