" Mole fraction of "I_(2)" in "C_(6)H_(6)" is "0.2" calculate molality of "I_(2)" in "C_(-)6H_(-)" 6"(MWC_(-)6H_(-)6=78gmol/-1})

Mole fraction of I_(2) in C_(6) H_(6) is 0.2. Calculate molality of I_(2) in C_(6) H_(6) . (Mw of C_(6) H_(6) = 78 g mol^(-1))

Mole fraction of I_(2) in C_(6) H_(6) is 0.2. Calculate molality of I_(2) in C_(6) H_(6) . (Mw of C_(6) H_(6) = 78 g mol^(-1))

Mole fraction of I_(2) in C_(6) H_(6) is 0.2. Calculate molality of I_(2) in C_(6) H_(6) . (Mw of C_(6) H_(6) = 78 g mol^(-1))

Mole fraction of I_2 in C_6H_6 is 0.2. Calculate molality of I2 in C_6H_6 .

Molefraction of I_(2) in C_(6)H_(6) is 0.2. The molality of I_(2) in C_(6)H_(6) is

The mole fraction of a given sample of I_(2) " in " C_(6)H_(6) " is " 0.2 . The molality of I_(2) " in " C_(6) H_(6) is:

Calculate the mole fraction of ethylne glycol (C_(2)H_(6)O_(2)) in a aqueous solution containing 20% of C_(2)H_(6)O_(2) by mass.

At 25^(@)C, K_(c ) for the reaction 3C_(2)H_(2(g))hArr C_(6)H_(6(g)) is 4.0. If the equilibrium concentration of C_(2)H_(2) is 0.5 mol. lit^(-1) . What is the concentration of C_(6)H_(6) ?