The points `(-2,5), (3, -4) and (7, 10)` are the vertices of the triangle then triangle is:

Explanation

Let `A(-2,5), B(3,-4) and C(7,10)` are the vertices of the given triangle.

Then,

`AB = sqrt((3-(-2))^2+(-4-5)^2) = sqrt106`

`BC= sqrt((10 - (-4))^2+(7-3)^2) = sqrt212`

`AC = sqrt((7-(-2))^2+(10-5)^2) = sqrt106`

Now, `AB = AC`

Also, `AB^2+AC^2 = BC^2`

So, `ABC` is a right angled isoceles triangle.