tan^(-1).(1)/(2)+tan^(-1).(1)/(3)=...

`tan^(-1).(1)/(2)+tan^(-1).(1)/(3)=`

A

`tan^(-1).(1)/(6)`

B

`(pi)/(3)`

C

`(pi)/(4)`

D

`(pi)/(6)`.

Verified by Experts

The correct Answer is:

C

tan^(-1).(1)/(2)+tan^(-1).(1)/(3)=
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