The differential equations, find a particular solution satisfying the given condition: `(dy)/(dx)-3ycotx=sin2x ; y=2`when `x=pi/2`

Explanation

Given,

`=>(dy)/(dx)​−3ycotx=sin2x`

`=>(dy)/(dx)​+(−3cotx)y=sin2x`

`=>(dy)/(dx)​+Py=Q`

here,

`P=−3cotx,Q=sin2x`

thus,`I.F=e^(∫Pdx)`

`=e^(∫(−3cotx)dx)`

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