" If "A_(1)sub A_(2)sub A_(3)sub---sub A_(300)" and "n(A_(i))=i+2," then "n[[300],[nnn],[i=10]]_(i),is

If A_(1)sub A_(2)sub A_(3)sub......sub A_(50) and n(A_(x))=x-1, then find n[nnn_(x=11)^(50)A_(x)]

For all p, such that 1<=p<=100 if n(A_(p))=p+2 and A_(1)sub A_(2)sub A_(3)sub......sub A_(100) and nnn_(p=1)^(100)A_(p)=A then n(A)=

For all p, such that 1 leple100 , if n(A_(p)) =p+2 and A_(1)subA_(2)subA_(3)sub. . . .subA_(100) and underset(p=3)overset(100)(cap)A_(p)=A , then n(A)=

If A_(1),A_(2),A_(3),... are sets such that n(A_(i))=101-iA_(1)sup A_(2)sup A_(3)sup...sup A_(100) and A=nnn_(i=5)^(100)A_(i) then n(A) is equal to

If A_(1),A_(2),..., A_(100) are sets such that n(A_(i))=i+2,A_(1)subA_(2)subA_(3)...subA_(100)and underset(i=3)overset(100)nnA_(i)=A,then n(A)=

If A_(1),A_(2),..., A_(100) are sets such that n(A_(i))=i+2,A_(1)subA_(2)subA_(3)...subA_(100)and underset(i=3)overset(100)nnA_(i)=A,then n(A)=

If n(A_(i))=i+1and A_(1)subA_(2)sub... subA_(99),then n(underset(i-1)overset(99)UA_(i))=