(2x-1)(x-3)=(x+5)(x-1)

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(2x-1)/((x-1)(2x+3))=1/(5(x-1))-k/(5(2x+3)) , then k =

((2x-1)/((x-1)(2x+3))=(1)/(5(x-1))+(k)/(5(2x+3))rArr k=

solve for x (2x-5)/(3x-1)=(2x-1)/(3x+2)

The equation is true for (12x+1)/(4)=(15x-1)/(5)+(2x-5)/(3x-1)

(3)/(x+1)-(2)/(x-1)=(5)/(x^(2)-1)

Solve ((2x+1)!)/((x+2)!)xx((x-1)!)/((2x-1)!)=(3)/(5)(x in N)

(x^(2)+5x+1)/((x+1)(x+2)(x+3))=(A)/(x+1)+(B)/((x+1)(x+2))+(C)/((x+1)(x+2)(x+3)) then B=

(1)/(2x+1)+(1)/(3)(1)/((2x+1)^(3))+(1)/(5)(1)/((2x+1)^(5))+....=

(3x-2)/(5x-1)=(3x+1)/(5x+2)

Add :5x^(2)-(1)/(3)x+(5)/(2),-(1)/(2)x^(2)+(1)/(2)x-(1)/(3) and -2x^(2)+(1)/(5)x-(1)/(6)