x^(6)-729

In the following questions two equation numbered I and II are given You have to solve both equations and give answer (i) x^(2)=729 (ii) y=sqrt(729)

729x^(6)-y^(6)

Factorise : 64x^3-729y^3

(2 + 5 omega + 2 omega ^ (2)) ^ (6) = (2 + 2 omega + 5 omega ^ (2)) ^ (6) = 729

Factorize the following polynomials x^(3)y^(3)+729

r^(3)=729 then r=?

A particle of mass 3 kg moves in aone dimensional field along x-axis. The force due to the field depends on its position as F= 729 x^(6) - 64 . Find the state equilibrium position. Determine the time period of osciallations for small amplitude osciallations about the stable equlibrium position.

A particle of mass 3 kg moves in aone dimensional field along x-axis. The force due to the field depends on its position as F= 729 x^(6) - 64 . Find the state equilibrium position. Determine the time period of osciallations for small amplitude osciallations about the stable equlibrium position.

The following steps are involved in finding the value of 3^(n-3) , when 3^n=729 . Arrange them in seqential order. (A) 3^(n-3)=3^(6-3)=3^3=27 (B) rArrn=6 (C) 3^(n)=729rArr3^n=3^6