Home
Class 12
MATHS
The taxi fare is Rs. 3.50 for 1 km or le...

The taxi fare is Rs. 3.50 for 1 km or less from start and Rs. 1.50 per km or any fraction thereof, for additional distance. If the fare be Rs. Y for a distance of x km, express y as a function of x.

Promotional Banner

Topper's Solved these Questions

  • RELATION AND MAPPING

    CHHAYA PUBLICATION|Exercise Multiple choice question|28 Videos

  • RELATION AND MAPPING

    CHHAYA PUBLICATION|Exercise Very short answer type questions|80 Videos

  • REAL NUMBERS

    CHHAYA PUBLICATION|Exercise Exercise (Long Answer Type Questions)|10 Videos

  • RELATION AND FUNCTIONS

    CHHAYA PUBLICATION|Exercise JEE Advanced Archive|3 Videos

Similar Questions

Explore conceptually related problems

The taxi fare is Rs. 3 for 1 km or less from starting point and Rs. 1.20 per km or any fraction thereof, for additional distance. If the fare be Rs. Y for a total journey of x km, express y as a function of x.

If y=f(x)=(x-3)/(2x+1)and z=f(y), express z as a function of x.

Find the distance of the point (-1, 1) from the line 12 (x + 6) = 5 (y - 2) .

Find the distance of the plane 2x-y+2z+1=0 from the origin.

Find the perpendicular distance of the straight line 4x-y=5 from the point (2,-1)

What are the points on the y-axis whose distance from the line x/3 + y/4 = 1 is 4 units.

Find the points on the x-axis, whose distances from the line x/3 + y/4 = 1 are 4 units.

Prove that the perpendicular distance of the line 3x+4y+5 =0 from origin is 1 unit.

A man has to spend Rs.16 per km on petrol if he rides his motor-car at 30 km per hour and the cost on petrol rises to Rs.20 per km if he rides his car at 45 km per hour. He has Rs.200 to spend on petrol and desires to travel maximum distance within 2 hours. Formulate the given data in the form of inequations and show graphically the region representing the solution of the inequations.